1.25x^2+.0875x=4.5

Solution for 1.25x^2+.0875x=4.5 equation:

1.25x^2+.0875x=4.5

We move all terms to the left:

1.25x^2+.0875x-(4.5)=0

We add all the numbers together, and all the variables

1.25x^2+.0875x-4.5=0

a = 1.25; b = .0875; c = -4.5;
Δ = b2-4ac
Δ = .08752-4·1.25·(-4.5)
Δ = 22.50765625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(.0875)-\sqrt{22.50765625}}{2*1.25}=\frac{-0.0875-\sqrt{22.50765625}}{2.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(.0875)+\sqrt{22.50765625}}{2*1.25}=\frac{-0.0875+\sqrt{22.50765625}}{2.5}
$